As we're getting further into hockey season and there have already been some amazing shots, I wanted to look at the physics behind one of the most impressive shots in the sport to pull off, the slap shot. I wanted to find out how much force was exerted by the puck on a goalie and how much work was done by the puck during a slap shot.
Assumptions:
- the puck was at rest before it was hit
- the puck was about 40 ft away from the goalie
- the puck accelerated at a constant rate
What we know:
- mpuck = 6 ounces = 0.17 kg
- vo = 0 m/s
- vf = 108.8 mph (fastest slap shot ever recorded in NHL) = 48.6 m/s
- t = 0.5 s
- d = 40ft = 12.192 m
Calculations:
- a = (vf - vo) / t = (48.6 - 0) / 0.5 = 97.25 m/s^2
- F = ma = .17(97.25) = 16.53 N
- W = Fd = 16.53(12.192) = 201 J
For an object with such a small mass, a hockey puck can sure impact a goalie with a decently-sized force when it is propelled forward by a slap shot. It also does quite a bit of work.
Resources:
http://sportsillustrated.cnn.com/nhl/news/20130308/top-10-nhl-slap-shots-of-all-time/
Thanks for for the information. Peace, Tex
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