A volleyball player’s approach and arm swing when they hit is
very intentional and can be quite intricate. The angle of approach, depth of
wind up, shoulder rotation, and hand contact and length of contact with the
ball are just a few technicalities that ultimately affect the ball’s direction
and velocity. But let’s try to simplify it in order to calculate the force I
can exert on the ball.
If I hit a 0.28kg volleyball at 80mph or about 36m/s (close to the top male Olympic speeds, but let's just pretend!), that means the ball
had a momentum of 10.1 kgm/s because p=mv.
We will assume the ball started at rest. This is decently
accurate because when the ball leaves the setter’s hands it is traveling
parallel to the net. We will assume I am hitting ‘down the line’, which means I
am manipulating the ball with my arm swing and wrist to cross the net
perpendicularly. So the ball was only moving in the x-direction before I hit
it, and afterwards it moves in the y-direction.
We know that F= Δp/Δt. Contact time between my hand and the ball depends on what I want the
ball to do. If I want the ball to have top-spin and drop quickly to the floor
my fingers wrap around the ball and I remain in contact with it longer. If I
want the ball to ‘float’ I make very brief contact with the ball with mostly my
palm.
Let’s say I want the ball to float
and that t=0.008 seconds. That leads us to: F= 10.1kg/s * 0.008s. F= 1262.5 N.
So a volleyball player’s arm is really quite the weapon!
P.S. Notice how the figure's knees are buckling inward before he jumps? That reduces the amount of force they can put into their jump. BAD FORM
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