Launch Angle: 30 degrees
Exit Velocity: 110.5 mph (49.4 m/s)
Distance: 481 feet (146.6 m)
Initial height: waist ≈ 0.9 m
First I had to find the velocity of the y-component through some trigonometry (sin30=opposite/49.4 m/s). The velocity of the y-component was found to be 24.7 m/s. At the ball's peak, the velocity of the y-component will be 0 m/s. With a simple kinematics equation, I was able to find the height of the home run.
vf^2=(vo^2)+2a(yf-yo)→0^2=(24.7^2)+2(-9.8)(yf-0.9)
The height was found to be 32.03 m (105.1 ft). (Ignoring air resistance)Last year at the baseball game, if someone would have asked me to calculate how high the ball went, I would have had no idea how to do it. I am proud that it is now just a simple physics problem for me. I am also very surprised that this stat was not recorded because it is so simple to find. After preparing this blog post, I am unsure if I will ever be able to watch baseball the same way again.
Source:
https://www.cubshq.com/update/WATCH-Baez-absolutely-destroys-baseball-on-481-foot-moonshot-Cubs-longest-homer-of-season-25398
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