By Alex Girden
What we Know
Distance
=63 yards
1
yard=0.9144 meters
Distance=58
meters
Height
of cross bar =10. feet
1
foot=0.3048 meters
Height
=3.0 meters
Football=
0.413 kg
Estimated
time of travel = 3 seconds
The easy idea
Solving
for initial velocity?
Angle
of kick?
Kinetic
Energy?
Calculations
Δx=vot+1/2at^2
3.o=vo
(3 s)+ 0.5*-9.8* (3)^2
Voy=16
m/s
Max
height- Vf^2=Vo^2+2aΔx
Δx=13
meters
More equations
Δx=vot+1/2at^2
ax=0
m/s^2
58=vo
(3)
Vox=19
m/s
Vnet^2=vx^2
+vy^2
Vnet=25
m/s
Unknowns
sinΘ=16/25
Θ=40
°
Kinetic
Energy given to ball
KE=1/2mv^2
½
(0.413kg) (25)^2=129 J
Force of a kicker
Time
in contact with ball approximate=1.8 X 10^-3 s
Vf=vo+at
25=0
+ a (1.3X 10^-3)
Acceleration
= 19,200 m/s
Force=ma=
(19,200 * 0.413 kg)=7,900 N
Future Directions
Take
into account wind speed and direction
Air
resistance’s affect on the ball
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