Since recently we have been
learning about rotation, that is what I focused on when looking at the physics of hockey.
Hockey has quite a lot of physics involved but I am only going to be focusing
on the physics of the lacrosse style goal in hockey. This type of goal occurs
when a player moves his stick at such a high velocity that he is able to scoop
the puck off the ice and throw it into the goal, like one does in lacrosse,
hence the name.

To do this the player must first
flip the puck on its side so it has contact with the whole blade of the stick. Then
the player guide the puck in a curved trajectory causing the puck to feel
centripetal force and experience centripetal acceleration. For this to work,
the velocity must be fast enough that the centripetal force pushing the puck
against the stick is enough to overcome the force of gravity. The friction
between the puck and stick must be sufficient enough that the puck will not
fall.

To
calculate how much speed a player would need to do this I am going to estimate
the the coefficient of friction between the puck and the stick to be 0.2. The mass
of the average hockey puck is 163 g. Finally the average height of an NHL
player is 6’ 2” (1.8876 m) and the average player has a stick that goes to the
height of his nose, which I will estimate is halfway down the face. The average
male face is 21.8cm tall, so the average stick height will be estimated to be
1.7786 m (the average height of a player, subtracted by half the length of the
average male face). This is what I will assume to be the radius.

F

_{FR}=mg
µF

_{N}=mg
(0.2)F

_{N}=(0.163)(9.8)
F

_{N}=7.897 N
F

_{N}=(mv^{2})/r
7.987=(0.163v

^{2})/1.7786
V=9.34 m/s

As a reference the
average speed of a player is 12.5 m/s.

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