Lanky like me? Don't be ashamed of your push-up count.
If we generalize and say that my longer legs cause my center of gravity to be 1.25x further away from my feet, and that I weigh 1.25x his weight, we can plug mass and center of gravity length (as r) into
Torque=rFsinΘ
Torque=(1.25)(1.25)sin90
Torque=1.6 Nm
Thus, there is 1.6x as much torque acting on me due to gravity than my friend. In order to counteract that gravity and hold myself up above the ground, I must apply a force while pushing up of at least
Torque=rFsinΘ
1.6=(77 inches/69 inches)FsinΘ
1.6=1.12Fsin90
F=1.43 N
1.43x as much as my friend. And this doesn't even begin to take into account the length of my arm, which means that I would have to apply a larger force over a longer distance, requiring more energy. I'll be showing him these numbers next time we do push-ups.
By Chris Wetzel
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.