In my EMT training we learned about the different kinds of
treatments we would need to perform for conditions that occur due to extreme
environmental factors, such as hypothermia. Right now, people, and
especially college students who may have altered judgment, need to be extremely
careful about dressing appropriately for the weather when going outside. Every
year we hear about college students freezing to death after leaving parties in
the winter. I decided to look into the net rate of heat flow from a human who
is scantily clad vs. the heat flow when wearing a thick down coat on a night
like tonight, which will feature a temperature of 20°F (-6.7° C, 266.3 K) at midnight.
For the scantily clad person we need to consider radiation
using this equation for the net rate of heat flow:
Q/t= eσA(T14 –T24)
Given the A of a person=1.7m2, the ehuman skin=
0.98, and the human body temperature of 310 K
Q= (0.98)(5.67 x 10-8 W/m2K4)(1.7m2)((310K)4-(266.3K)4)
Q=397 W
When wearing a coat the person is insolated by the air contained
within the ~2in (.05m) of down (assume the coat covers the whole body).
We can find the heat transfer based on conduction:
Q/t= KA((T1 –T2)/l)
Given the cross-sectional area of a person is ~0.5m2,
the thermal conductivity constant of air is 0.024 W/mK, and the distance
between the two temperatures is the thickness of the coat
Q=(0.024 W/mK)( 0.5m2)((310K-266.3K)/.05m)
Q=10.4 W
Obviously, the cross sectional area of a person is less than
the total surface area used in the calculation of radiation. However, one can still
see that much less heat is transferred to the environment when wearing a coat. Jacket thieves run rampant at Colgate, as evidenced by the frequent pleas for the return of coats on the class Facebook pages. We can see here how important coats are for maintaining body heat, and should be more careful to bring our own outerwear and not steal that of others!
References:
http://onlinelibrary.wiley.com/store/10.1256/wea.29.02/asset/2002571103_ftp.pdf?v=1&t=iwidutfm&s=018b03ff369ae002c3a08fb1b7b4b7b8a8ff3287
https://weather.com
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