An Olympic bar with weighs 20kg, and is 2.13m long, and on the right side we are assuming that there are three 20kg plates, totaling 60kg 0.25m from the axis of rotation. There is no weight on the left side of the bar. It is also important to note that the axis of rotation is not at the end of the bar, it is roughly 0.45m from the end.
The net torque is then: Σ = (right) - (bar) when the right side is heavier.
Using the torque equation =(r)(F)(sinθ), the equation is as follows:
Σ =(.25m)(60kg*9.8m/s^2) - (.6m)(20*9.8m/s^2) = 147N-118N= 29N in the clockwise direction.
As you can see, a difference of three plates on a standard Olympic bar will cause a net torque to be created in the system, sending the bar swinging with potential for serious injury.
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