Physics News

Every
Sunday morning, I wake up and do the same thing, I go for a run, eat breakfast,
and watch soccer. This weekend, I began to think about the rotational motion of
a passed soccer ball because a ball when passed rolls without slipping. I decided to then try and figure out what the
average angular velocity, centripetal acceleration, and overall kinetic energy
of a passed ball. I guess the average speed of a pass to be 15 mph or 6.7 m/s,
and the ball has a radius of 0.22m[1];
therefore I am able to calculate the angular velocity of the ball:

W=6.7/0.22

W=30.5rad/s

I also decided to find the centripetal acceleration for the
average free kick in soccer:

A= 6.7

^{2}/0.22
A=204 rad/s

Next, I wanted to figure what the overall kinetic energy of
a ball is as it moves over the ground. So, I saw that the average soccer ball
weighs 15 oz. or .43 kg. Therefore, one can solve for the kinetic energy of the
system.

KE=1/2(.43)(6.7)

^{2}+1/2(I)(30.5)
I=2/5(.43)(.22)

^{2}
KE=9.78 J

Therefore, a soccer player must due 9.78 J of work in order
to pass a soccer ball.

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