By Clara Slight
I have swum all my life. Since we
learned recently about drag force, I decided to calculate the drag force that
is encountered while swimming. I decided to calculate this for two different
aspects: for your hand while swimming freestyle and then for your entire body.
When you take a stroke while swimming, your hand is moving faster than your
entire body. I made some estimates, and used a velocity of 3 m/s, a
cross-sectional area of .10 m, a viscosity of water of 8.9*10-4, and
a coefficient of drag of a half sphere or .42 (http://swimright23.webs.com/dragandresistance.htm).
The drag force that a hand encounters while swimming freestyle is Fd
= 1/2pCdv2A = ½(8.9*10-4)(.42)(32)(.1)
= 1.68*10-4 N. For the entire body, the calculations change. I also
made some estimates here, using a velocity of 1 m/s, a cross-sectional area of
.4 m, the same viscosity of water, a coefficient of drag of a streamlined half
body or .09. The drag force that a body encounters while swimming freestyle is
Fd = 1/2pCdv2A = ½(8.9*10-4)(.09)(12)(.4)
= 1.60*10-5. It is interesting to note that when a swimmer is
completely submerged, the drag coefficient decreases to .04 and the subsequent
drag force is less. The calculated value is Fd = 1/2pCdv2A
= ½(8.9*10-4)(.04)(12)(.4) = 7.12*10-6. It is
also interesting to observe that as the velocity increases, so does the drag
force, which makes sense.
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