Snow forms when it is 0 degrees C.

Assume there is 0.5m of snow.

Assume also that the area of the measured plot is 0.2m by 0.3m.

Thermal conductivity of snow is 0.05- 0.7 WK-1m-1

Assume that soil temperature is 39.7 degrees F (4.28 degrees C) in December (when it begins to snow)

Thus, using the lower scale of thermal conductivity,

Q/T = (k * A * (T2 - T1)) / l

Q/T = (0.05 * 0.2 * 0.3 * (4.28 - 0)) / 0.5

Q/T = 0.02568

Using the higher scale of thermal conductivity,

Q/T = (k * A * (T2 - T1)) / l

Q/T = (0.7 * 0.2 * 0.3 * (4.28 - 0)) / 0.5

Q/T = 0.35952

Emissivity constant of snow is 0.969 - 0.997.

Boltzman Constant is 5.67 X 10^-8

T1 = 273K

T2 = 312.7K

Now, looking at albedo effects, (using the lower end of emissivity constant)

Q/T = eoA(T1^4 - T2^4)

Q/T = (0.969)(5.67 X 10^-8)(0.2 X 0.3)(273^4 - 312.7^4)

Q/T = -13.21

Using the higher end of emissivity constant,

Q/T = eoA(T1^4 - T2^4)

Q/T = (0.997)(5.67 X 10^-8)(0.2 X 0.3)(273^4 - 312.7^4)

Q/T = -13.59

From this, we can see that the heat flow due to radiation is greater than the heat flow due to insulation (which is true because although snow has a lot of air, it is still very cold and cannot insulate the soil as much since the soil temperature is much higher).

References

https://nsidc.org/cryosphere/snow/science/formation.html

http://www.cnyweather.com/wxsoil.php

http://www.engineeringtoolbox.com/radiation-heat-emissivity-d_432.html

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